Integrand size = 23, antiderivative size = 35 \[ \int \frac {\cot (c+d x)}{\sqrt {a+b \sin ^4(c+d x)}} \, dx=-\frac {\text {arctanh}\left (\frac {\sqrt {a+b \sin ^4(c+d x)}}{\sqrt {a}}\right )}{2 \sqrt {a} d} \]
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Time = 0.12 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {3308, 272, 65, 214} \[ \int \frac {\cot (c+d x)}{\sqrt {a+b \sin ^4(c+d x)}} \, dx=-\frac {\text {arctanh}\left (\frac {\sqrt {a+b \sin ^4(c+d x)}}{\sqrt {a}}\right )}{2 \sqrt {a} d} \]
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Rule 65
Rule 214
Rule 272
Rule 3308
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1}{x \sqrt {a+b x^2}} \, dx,x,\sin ^2(c+d x)\right )}{2 d} \\ & = \frac {\text {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,\sin ^4(c+d x)\right )}{4 d} \\ & = \frac {\text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \sin ^4(c+d x)}\right )}{2 b d} \\ & = -\frac {\text {arctanh}\left (\frac {\sqrt {a+b \sin ^4(c+d x)}}{\sqrt {a}}\right )}{2 \sqrt {a} d} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00 \[ \int \frac {\cot (c+d x)}{\sqrt {a+b \sin ^4(c+d x)}} \, dx=-\frac {\text {arctanh}\left (\frac {\sqrt {a+b \sin ^4(c+d x)}}{\sqrt {a}}\right )}{2 \sqrt {a} d} \]
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Time = 0.62 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.20
method | result | size |
default | \(-\frac {\ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {a +b \left (\sin ^{4}\left (d x +c \right )\right )}}{\sin \left (d x +c \right )^{2}}\right )}{2 d \sqrt {a}}\) | \(42\) |
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Time = 0.35 (sec) , antiderivative size = 140, normalized size of antiderivative = 4.00 \[ \int \frac {\cot (c+d x)}{\sqrt {a+b \sin ^4(c+d x)}} \, dx=\left [\frac {\log \left (\frac {8 \, {\left (b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} - 2 \, \sqrt {b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} + a + b} \sqrt {a} + 2 \, a + b\right )}}{\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1}\right )}{4 \, \sqrt {a} d}, \frac {\sqrt {-a} \arctan \left (\frac {\sqrt {b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} + a + b} \sqrt {-a}}{a}\right )}{2 \, a d}\right ] \]
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\[ \int \frac {\cot (c+d x)}{\sqrt {a+b \sin ^4(c+d x)}} \, dx=\int \frac {\cot {\left (c + d x \right )}}{\sqrt {a + b \sin ^{4}{\left (c + d x \right )}}}\, dx \]
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Time = 0.31 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.43 \[ \int \frac {\cot (c+d x)}{\sqrt {a+b \sin ^4(c+d x)}} \, dx=\frac {\log \left (\frac {\sqrt {b \sin \left (d x + c\right )^{4} + a} - \sqrt {a}}{\sqrt {b \sin \left (d x + c\right )^{4} + a} + \sqrt {a}}\right )}{4 \, \sqrt {a} d} \]
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Timed out. \[ \int \frac {\cot (c+d x)}{\sqrt {a+b \sin ^4(c+d x)}} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {\cot (c+d x)}{\sqrt {a+b \sin ^4(c+d x)}} \, dx=\int \frac {\mathrm {cot}\left (c+d\,x\right )}{\sqrt {b\,{\sin \left (c+d\,x\right )}^4+a}} \,d x \]
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